(5x^-1-(4y)^-1)/(x-2)=0

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Solution for (5x^-1-(4y)^-1)/(x-2)=0 equation: 


D( x )

x-2 = 0

x = 0

4*y = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x = 0

x = 0

4*y = 0

4*y = 0

4*y = 0

x naleu017Cy do R

x belongs to the empty set

(5*x^-1-(4*y)^-1)/(x-2) = 0

x belongs to the empty set

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